Y³ + 1/8y³ factor this example
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HEYA MATE, HERE IS UR ANSWER ___________________________
Y^3+1/8Y^3
=(y)^3+(1/2y)^3
Using identity a^3 +b^3 =( a+b)(a^2-ab+b^2)
=(y+1/2y){y^2-y×1/2y+(1/2y)^2}
=(2y^2+1/2y)(y^2-1/2+1/4y^2)
________☆☆HOPE THE ANSWER HELPS YOU ☆☆______☆☆BE BRAINLY ☆☆☆______☆
Y^3+1/8Y^3
=(y)^3+(1/2y)^3
Using identity a^3 +b^3 =( a+b)(a^2-ab+b^2)
=(y+1/2y){y^2-y×1/2y+(1/2y)^2}
=(2y^2+1/2y)(y^2-1/2+1/4y^2)
________☆☆HOPE THE ANSWER HELPS YOU ☆☆______☆☆BE BRAINLY ☆☆☆______☆
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2
y³+1/8y³
=(y)³+(1/2y)³
using identity a³+b³= (a + b)(a² - ab + b²)
a=y b=1/2y
(y)³+(1/2y)³=(y+1/2y)(y²-y²/2+1/4y²)
=(3y/2)(3y²/4)
=9y³/8
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