Question

(y³-216)÷(y-6)

pls give the right Answer

STD lX ​

Answer 1

Answer:

y^2+6y+36 is the right answer.

plz mark this as a brainliest answer

Answer 2

$\frac{y³-216}{y-6}$

$= \frac{y³-6³}{y-6}$

$= \frac{(y-6)(y²+y×6+6²}{ y-6}$

${\purple{\bf ►By \:algebraic \:identity: }} \\ {\purple{\bf \: \:\: \: \:\:\:\:\:a³-b³ = (a-b)(a²+ab+b²)}}$

$\tt =y²+6y+36$

∴ $\tt \frac{y³-216}{y-6} = y²+6y+36$