Question

(y³-216)÷(y-6)


solve this ​

Answer 1

Answer:

$\frac{y^{3}-216}{y-6}=y^{2}+6y+36$

Step-by-step explanation:

$\frac{y^{3}-216}{y-6}\\=\frac{y^{3}-6^{3}}{y-6}\\=\frac{(y-6)(y^{2}+y\times6+6^{2})}{y-6}$

\* By algebraic identity:

a³-b³ = (a-b)(a²+ab+b²) */

$=(y^{2}+6y+36)$

Therefore,

$\frac{y^{3}-216}{y-6}=y^{2}+6y+36$

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Answer 2

hey friend

the answer is in the given attachment.

please mark as brainliest.