Math, asked by dondongh30031981420, 4 months ago

y³-27/5y²-16y+3÷y²+3y+9/25y²-1​

Answers

Answered by gopalpvr
2

Step-by-step explanation:

y³-27/5y²-16y+3÷y²+3y+9/25y²-1

y³-27 / (5y-1)(y-3) ÷ (y²+3y+9)/(5y-1)(5y+1)

(y-3) (y²+3y+9) / (5y-1)(y-3) * (5y-1)(5y+1) / (y²+3y+9)

=(5y+1)

so y³-27/5y²-16y+3÷y²+3y+9/25y²-1 = (5y+1)

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