Question

(y3-27) expand eight standard​

Answer 1

Answer:

(y - 3)(y^2 + 3y + 9)

Step-by-step explanation:

y^3-27

= (y)^3 - (3)^3

= (y - 3)(y^2 + 3y + 3^2)    [∵ using a^3 - b^3 = (a-b)(a^2 + ab + b^2)

= (y - 3)(y^2 + 3y + 9)

Answer 2

Step-by-step explanation:

in this we can see cubic power and then we have 27 which is the cube by that we have solved it. please follow my channel