y3-3xy2-x2y+3x3-3x2+10xy-3y2-10x-10y+7=0
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Answer:
Given, 3x
2
+10xy+8y
2
+14x+22y+7=0
standard form of hyperbola is
a
2
x
2
−
b
2
y
2
=1 Asymptotes:-
a
2
x
2
−
b
2
y
2
=0
So,
=3x
2
+10xy+8y
2
+14x+22y+10=0
This is pair of straight lines.
a=3,b=8,g=7,b=11,n=5,c=k
∣
∣
∣
∣
∣
∣
∣
∣
a
h
g
h
b
b
g
b
c
∣
∣
∣
∣
∣
∣
∣
∣
=0
⇒
∣
∣
∣
∣
∣
∣
∣
∣
3
5
7
5
8
11
7
11
k
∣
∣
∣
∣
∣
∣
∣
∣
=0
⇒3(8k−121)−5(5k−77)+7(55−56)=0
⇒24k−363−25k+385−7=0
⇒−k−370+385=0
∴k=15
Asymptotes are :-
3x
2
+10xy8y
2
+14x+22y+15=0
Step-by-step explanation:
hope this helps you.
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Answer:
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