y3- [y2-(y3+y2 ]-[y3+(1-y2)] simplify
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Answer:
y3- [y2-(y3+y2 ]-[y3+(1-y2)] simplify
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Step-by-step explanation:
y*3-[y*2-(y*3+y*2)]-[y*3+(1-y*2)]
=y*3-[y*2-y*3-y*2]-[y*3+1-y*2]
=y*3-[-y*3]-y*3-1+y*2
=y*3+y*3-y*3-1+y*2
=y*3+y*2-1
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