Question

(y4-2x3y)dx+(x4-2xy3)dy=0​

Answer 1

Answer:

d=0/x³+y³

Step-by-step explanation:

Let's solve for d.

(y4−2x3y)(d)x+(x4−2xy3)(d)y=0

Step 1: Factor out variable d.

d(−x4y−xy4)=0

Step 2: Divide both sides by -x^4y-xy^4.

d(−x^4y−xy^4)/−x^4y−xy^4

=0−x^4y−xy^4

d=0/x³+y³

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