y4 - 3y2 + 2y +1/ y-1
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Step-by-step explanation:
By remainder theorem we know that if p(y) is divided by g(y ) = y-1 then the remainder will be p(1)
therefore, p(1)= 1^4-3(1)^2+2(1)+1
= 1-3+2+1= 1-3+3 = 1
therefore the remainder is 1
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