Question

y⁵+y⁴+y³+y²+y+1 by y³+1​

Answer 1

$\huge\bold\green{꧁}$$\huge\pink{\fbox{\sf{ Lucky }}}$$\huge\bold\green{꧂}$

$= > \frac{ {y}^{5} + {y}^{4} + {y}^{3} + {y}^{2} + y + 1}{ {y}^{3} + 1}$

• cancel y³ and 1

$= > {y}^{5} + {y}^{4} + {y}^{2} + y$

${y}^{5} + {y}^{4} + {y}^{2} + y = {y}^{5 + 4 + 2 + 1}$

=> ${y}^{12}$ ☑️