(ya²+ya+1) ÷ (2a +1)
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Step-by-step explanation:
x=2a+1−2a−12a+1+2a−1=(2a+1−2a−1)(2a+1+2a−1).(2a+1+2a−1)(2a+1+2a−1)=2a+1−2a+1(2a+1+2a−1)2=22a+1+2a−1+2(2a+1)(2a−1)⇒2x=4a+2(2a)
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