Question

Yaar solve Kardo....​

Answer 1

Answer:

One simple method you can use.

We know that sum of first 1 term(s) is the first term itself.

So substitute n=1 in the expression S=6-7n²

We get S1 = a = 6-7 = -1. (a=first term)

Let 'd' be the common difference.

Now, S2 = a + (a+d) = 2a + d

Substituting n = 2,

2a+d = 6 - 7*4 = 6-28 = -22

or -2 + d = -22

or d = -20.

Now 7th term is a + 6d = -1 + 6(-20) = -121

and the common difference is -20.

So the magnitude of difference between these two values is |-121 - (-20)| = |-101| or 101.

101 is the required difference.

Answer 2

Answer:

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