Question

yaaron madat kar do please na​

Answer 1

Answer:

1/3

Step-by-step explanation:

We have to solve question no (i)

Given :-

${( {2}^{0} + {3}^{ - 1})} \times {4}^{ - 1} \\ (1 + \frac{1}{3}) \times \frac{1}{4} \\ (\frac{3 + 1}{3}) \times \frac{1}{4} = (\frac{4}{3}) \times \frac{1}{4} \\ \frac{4}{3} \times \frac{1}{4} = \frac{1}{3} \\ where \: {m}^{0} = 1 \: \: \: ({2}^{0} = 1)\\ {m}^{ - 1} = \frac{1}{m} = ({3}^{ - 1}) = \frac{1}{3}$