Question

yadi 10 power 2 Y barabar 25 to the power minus y barabar hai​

Answer 1

Answer:

10^2y=25^-y

(5^2y) (2^2y) =5^2(-y)

bringing rhs in denominator on lhs

5^(2y-(-2y)) (2^2y) =1

(5^4y) (2^2y) =1

(10^2y) (5^2y) =1

taking log base 10 on both sides

so,

2y(log10) +2y(log5) =1

2y+2y*0.7=1

3.4y=1

y=0.29=0.30