Math, asked by mehakthakur077, 9 months ago

yadi x+y+z=15,xy+yz+zx=71 aur xyz=10 ho to x3+y3+z3 ka maan nikale​

Answers

Answered by visheshnagar1812
0

Answer:210

Step-by-step explanation:

x3+y3+z3-3xyz=(x+y+z)(x2+y2+z2-xy-yz-zx)

x3+y3+z3=3xyz+(x+y+z)(x2+y2+z2-xy-yz-zx)

=3xyz+(x+y+z)((x+y+z)2-2(xy+yz+zx)-(xy-yz-zx))

=3xyz+(x+y+z)((x+y+z)2-3(xy+yz+zx))

=3x10+(15((15)^2-3x71))

=30+15(12)

=30+180

=210

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