Question

yah (- 4, - 2)( - 3 - 5) (3, - 2), (2,K) the vertices of a quadrilateral ABCD find the value of k if the area of quadrilateral is 28 square units​

Answer 1

Step-by-step explanation:

area =28

area of one triangle =28/2=14sq.units

$area = 1 \div 2(x1 +(y2 - y3) + \\ x2(y3 - y1) + x3(y1 - y2))$

-4=x1 -2=y1

3=x2 -2=y2

2=x3 k=y3

14=1/2((-4)(-2-k)+3(k+2)+2(-2-2))

14=1/2(8+4k+3k+6-8)

14=1/2(7k+6)

28/7=k+6

4-6=k

-2=k.

Answer 2

Answer:

answer attached in photo