Question

yah can do a piece of work in 20 days and B can do it in 12 days B worked for 9 days in how many days a alone can finish the remaining work ​

Answer 1

Gɪᴠᴇɴ :-

• A can do a piece of work in 20 days.
• B can do it in 12 days..
• B worked for 9 days..

Tᴏ Fɪɴᴅ :-

• In how many days A alone can finish the remaining work ?

Sᴏʟᴜᴛɪᴏɴ :-

LCM of 20 & 12 = 60 units = Let Total work.

So,

→ Efficiency of A = (Total work) / (Total Days Required) = 60/20 = 3 unit/day.

And,

→ Efficiency of B = (Total work) / (Total Days Required) = 60/12 = 5 unit/day.

Now, B Alone work for 9 Days.

So,

→ B complete work in 9 Days = 9 * 5 = 45 units.

Now,

→ Remaining work = 60 - 45 = 15 units.

This Has to Be Done by A alone Now.

Therefore,

→ A will Take = (Remaining work) / (Efficiency of A) = 15/3 = 5 Days. (Ans.)

Hence, A alone can finish the remaining work in 5 Days.