Question

Yah cube + 2 a square + 2A + 1 divided by a + 1

Answer 1

let a = x

${x}^{3} + 2 {x}^{2} + 2x + 1 \div x + 1 \\ = > \frac{ {x}^{3} + {x}^{2} + {x }^{2} + x + x + 1 }{x + 1} \\ = > \frac{ {x}^{2}(x + 1) + x(x + 1) + 1(x + 1) }{x + 1} \\ = > x {}^{2} + x + 1$

$= > \boxed{ \green{ {a}^{2} + a + 1 }} \\ this \: is \: the \: solution \: for \: this \: particular \: question \: \\ \large{hope \: \: it \: helps \: you}$