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In the above figure <A and <ACB are equal which is given.
So,Let <A and <ACB be x
So,ATQ,
<A+<ACB+<B=180°
x+x+80°=180°
2x+80°=180°
2x=180°-80°
2x=100°
x=50°
So,<A=x=50°.
<ACB=x=50°.
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ᴀɴɢʟᴇ ᴀ ɴᴅ ᴄ ʀ ᴇQᴜᴀʟ..............
ᴇxᴘʟᴀɴᴀᴛɪᴏɴ↷
ᴛʜᴇ ᴛᴏᴛᴀʟ ꜱᴜᴍ ᴏꜰ ᴀ ᴛʀɪᴀɴɢʟᴇ ɪꜱ 180,ꜱᴏ
ɢɪᴠᴇɴ:
ᴀɴɢʟᴇ ʙ= 80
ᴀɴɢʟᴇ ᴀ ɴᴅ ᴄ= 180-80= 100
2 ᴀɴɢʟᴇꜱ ᴏꜰ ᴀ ᴛʀɪᴀɴɢʟᴇ ɪꜱ ᴇQᴜᴀʟ, ꜱᴏ
ʜᴀʟꜰ ᴏꜰ 100= 100÷2= 50
∴ᴀɴɢʟᴇ ᴀ ɴᴅ ᴄ = 50°
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