yarr exam chal raha ha answer please dedo
Answers
Step-by-step explanation:
A room 5 m long, 4.5 m wide and 3.6 m high has one door 1.5 m by 2.4 m and two windows, each 1 m by 0.75 m. Find :
(i) the area of its walls, excluding door and windows ;
(ii) the cost of distempering its walls at the rate of Rs.4.50 per m2.
(iii) the cost of painting its roof at the rate of Rs.9 per m2.
surface area volume and capacity (cuboid cube and cylinder)
Length of the room = 5 m
Breadth of the room = 4.5 m
Height of the room = 3.6 m
Area of the roof = L × B
= 5 × 4.5 m2
= 22.5 m2
Area of four walls = 2[L + B] × H
= 2[5 + 4.5] × 3.6
= 2(9.5) × 3.6
= 19 × 3.6
= 68.4 m2
Area of one door = 1.5 × 2.4 m2
= 3.60 m2
= 3.6 m2
= 68.4 m2
Area of one window = 1 × 0.75 m2
= 0.75 m2
Area of 2 windows = 0.75 × 2 m2
= 1.5 m2
(i) Area of four walls excluding door and windows
= 68.4 – (3.6 + 1.5)
= 68.4 – 5.1
= 63.3 m2
(ii) Cost of distempering four walls @ Rs. 4.50 per m2
= 63.3 × 4.50
= Rs. 284.85
(iii) Cost of painting the roof @ Rs. 9 per m2
= 22.5 × 9
= Rs. 202 .50