Math, asked by acharyvikash6179, 10 months ago

Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1 mark for each wrong answer. Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then yash would have scored 50 marks. How many questions were there in the test?

Answers

Answered by sehej007
88

Answer: 20 questions

Step-by-step explanation: Let the no. of questions correctly attempted be x

and the no. of questions wrongly attempted be y

so,

case 1

3x - 1y = 40

case 2

4x - 2y = 50

2x - y =25

now on subtracting case 1 from 2 we get,

3x - 2x - y +y = 40 - 25

x = 15

putting in case 1 we get,

y = 5

total question= x + y

20 questions

Answered by nfatma551gmailcom
3

Yash scored 40marks in a test, getting 3marks for each right answer and losing1 mark for each wrong answer. Had 4marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks. How many questions were there in the test?Let correct question = xAnd incorrect question  = yYash scored 40 marks in a test, getting 3marks for each right answer and losing1 mark for each wrong answer.3x -  y = 40Subtract 3x both sides we get-Y = 40 – 3x        Change the sign we getY = 3x – 40 …(1)Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marksWe get4x – 2y = 50Plug the value of y we get4x – 2(3x - 40) =504x – 6x + 80 = 50-2x = - 30X = 15Plug this value back in equation first we getY = 3x – 40Y = 3* 15- 40Y = 45 – 40Y = 5

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