Math, asked by maahira17, 9 months ago

Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1 mark for each wrong answer. Had 4 marks been awanded for each correct answer and 2 marks been deducted for each incorrect answer, the Yash would have scored 50 marks. How many question were there in the test?

Answers

Answered by nikitasingh79
8

Given : Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1 mark for each wrong answer. Had 4 marks been awanded for each correct answer and 2 marks been deducted for each incorrect answer, the Yash would have scored 50 marks.

Solution:

Let the number of  right answers be x

And number of Wrong answers be y.

Total number of questions in the test =  x + y

 

CONDITION 1 :

Marks awarded for x right answers= 3x

Marks lost for y wrong answers = y×1= y

3x - y = 40………….(1)

 

CONDITION 2  :

Marks awarded for x right answers= 4x

Marks lost for y wrong answers = y×2= 2y

4x - 2y = 50…………(2)

Multiply equation 1 by 2 and subtract equation 2  :

6x - 2y = 80

4x - 2y = 50        [By elimination method]

(-)  (+)   (-)

-----------------

2x = 30

x = 30 /2

x = 15

 

On putting the value of x in equation 1 :

3x - y = 40

3(15) - y = 40

45 - y = 40

-y  = 40 - 45

-y = - 5

y = 5

Total number of questions in the test = x + y = 20 + 5 = 25.

Hence, there were total 25 questions in the test

Hope this answer will help you…

 

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Answered by VishalSharma01
80

Answer:

Step-by-step explanation:

Solution:-

Let number of correct answers be x

And the number of incorrect answers be y.

According to the Question,

3x - y = 40 … (i)

4x - 2y = 50 … (ii)

Solving Eq (i) and (ii), we get

6x - 2y = 80 … (iii)

Subtracting (ii) from (iii), we get,

⇒ 2x = 30

⇒ x = 30/2

x = 15

Putting x's value in Eq (i), we get

⇒ 3x - y = 40

⇒ 3(15) - y = 40

⇒ 45 - y = 40

⇒ y = 45 - 40

y = 5

Total number of questions = 15 + 5 = 20

Hence, 20 question were there in the test.

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