Math, asked by riharnitha3, 6 months ago

Yash scored 40 marks in a test getting 3 marks for each right answer and losing one mark for each wrong answer. had 4 marks been awarded for each correct answer and two marks been deducted for each incorrect answer, then years would have scored 50 marks .how many questions were there in the test ?



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Answers

Answered by navithasaravanan21
1

Answer:

Let number of correct answers be x

And the number of incorrect answers be y.

According to the Question,

⇒ 3x - y = 40 … (i)

⇒ 4x - 2y = 50 … (ii)

Solving Eq (i) and (ii), we get

⇒ 6x - 2y = 80 … (iii)

Subtracting (ii) from (iii), we get,

⇒ x = 15

Putting x's value in Eq (i), we get

⇒ y = 5

Total number of questions = 15 + 5 = 20

Hence, 20 question were there in the test.

Answered by Anonymous
3

Answer:

Let x be the number of right answers and y be the number of wrong answers.

∴ According to the question ,

3x−y=40⟶(i)

and , 2x−y=25⟶(ii)

On substraction : x=15

putting the value of x in ⟶(i)

3(15)−y=40

y=5

∴ Number of right answers=15 answers

Number of wrong answers=5 answers.

Total Number of questions 5+15=20

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