Question

yash scored 40 marks in a test .getting 3marks for each right answer and loosing 1 maek fir each wrong answér .had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer then yash would have scored 50marks how many questions were there in the test.?

Answer 1

Heya !!

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Let the number of correct questions be 'x' and the number of incorrect questions be 'y'.

A.T.Q.

3x – y = 40 _(1)
=> 3x – 40 = y

4x – 2y = 50 _(2)
=> 2x – y = 25

Now, substituting y = 3x – 40 in (2)
2x – (3x – 40) = 25
=> –y + 40 = 25
=> –y = 25 – 40
=> –y = –15
=> y = 15

Thus, total questions = x + y
=> 5 + 15
=> 20

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Hope my ans.'s satisfactory.☺

Answer 2

Answer:

$\huge{\mathcal{\underline{\green{Answer}}}}$

Let x be the number of right answers and y be the number of wrong answers.

∴ According to the question ,

3x−y=40⟶(i)

and , 2x−y=25⟶(ii)

On substraction : x=15

putting the value of x in ⟶(i)

3(15)−y=40

y=5

∴ Number of right answers=15 answers

Number of wrong answers=5 answers.

Total Number of questions 5+15=20