Yashvi rides a bicycle at a uniform speed. If the speed had been 4 km/hr more, it would
have taken 1 hourless to travel 48 km distance. Determine her speed.
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the force the answer will be six hour
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Given:
If speed had been 4km/hr more then she would take 1 hour less to travel 48 km.
To find:
Speed of Yashvi's bicycle.
Solution:
Let the time taken by the bicycle be t hrs to cover a distance of 48 km with a speed of S km/hr.
Then time t = distance/ speed
t = 48/S
When S is 4 km/hr more, then time taken is one hour less:
48/(S+4) = t-1
Putting the value of t from previous equation we get:
48/(S+4) = 48/S - 1
48/(S+4) = 48-S/ S
48S = (48-S)(S+4)
48S = 48S - S^2 + 192 -4S
S^2 + 4S - 192= 0
S^2 + 16S - 12S -192 = 0
S(S + 16) -12(S + 16) = 0
(S + 16)(S - 12) = 0
S = -16 and 12
Since speed cannot be negative therefore S = 12.
Therefore the speed will be 12 km/hr.
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