Math, asked by fencermohit8317, 4 months ago

Yashvi rides a bicycle at a uniforn speed. If the speed had been 4KM/HR more, it would have taken 1hour less to travel 48km distance. Determine her speed

Answers

Answered by mathdude500
3

\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\blue{W}\green{E}\pink{R}}}}</p><p></p><p>

\large\bold\red{case \: 1}

Let \:  the \:  uniform \:  speed  \: of \:  bicycle \:  be \:  x \:  km/hr. \\ </p><p>Distance \:  covered = 48  \: km. \\ </p><p>So, time  \: taken, t_1 =  \dfrac{48}{x}

\large\bold\red{case \: 2}

Now,  \: Speed \:  is  \: 4 \:  km/hr  \: more. \\ </p><p>So,  \: now \:  speed = (x + 4) km/hr\\ </p><p>Distance  \: covered  \: = 48 \:  km \\ </p><p>Time  \: taken, \:  t_2 =  \dfrac{48}{x + 4} </p><p>

\large\bold\red{According \:  to \:  statement }

\large\bold \blue{t_1 - t_2 = 1}

   = &gt;  \frac{48}{x}  -  \frac{48}{x + 4} = 1  \\  =  &gt;  \:  \frac{48(x +4 ) - 48}{x(x + 4)}  =  1\\  =  &gt;  \frac{48x + 192 - 48x}{ {x}^{2}  + 4x}  = 1 \\  =  &gt;  \: 192 =  {x}^{2}  + 4x \\  \\  =  &gt;  \:  {x}^{2}  + 4x - 192 = 0 \\  =  &gt;  \:  {x}^{2}  + 16x - 12x - 192 = 0 \\  =  &gt; x(x + 16) - 12(x + 16) = 0 \\  =  &gt;  \: (x + 16)(x - 12) = 0 \\  =  &gt; x = 12 \: or \: x =  - 16 \\ so \: it \: means \: x = 12

\boxed{ \large{ \mathfrak{So, \:  the \:  speed  \: of \:  bicycle  \: is \:  12 \:  km/hr}}}

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