Math, asked by devanshu2837, 8 hours ago

Yasir is fifteen years elder than Mujtaba. Five years ago, Yasir was three times as old as Mujtaba. Then Yasir’s present age will be:

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Answers

Answered by devanshu1234321
3

QUESTION:-

Yasir is fifteen years elder than Mujtaba. Five years ago, Yasir was three times as old as Mujtaba. Then Yasir’s present age will be:

EXPLANATION;-

Let the age of Yasir be = x years

Mujtaba will be equal to x – 15 years

in other condition we have,

Five years af Mujtaba five years ago will be x – 15 – 6 years = x – 21 years.

the age of Yasir will be equal to x – 5 years.

ATQ

3(x – 21) = x – 5 or

3x – 63 = x  – 5.

2x = 58 and

hence x = 29 years. Therefore Yasir’s present age is 29 years

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Answered by jhajhariasanshray
82

Yasir's present age is 27.5 years

Step-by-step explanation:

Let the present age of Mujtaba be x

We are given that Yasir is fifteen years elder than Mujtaba

So, Yasir's present age = x+15

Mujtaba's age 5 years ago = x-5

Yasir's age 5 years ago = x+15-5=x+10

Five years ago, Yasir was three times as old as Mujtaba.

x+10=3(x-5)

x+10=3x-15

25=2x

12.5 years =x

Yasir's present age = x+15=12.5+15=27.5 years

Hence  Yasir's present age is 27.5 years

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