Math, asked by Gurpindersingh4604, 8 months ago

यदि _12×(_3)+[20÷(_4)_(_24)÷8]_[16÷(_2]=(_28÷7)xहे तो xका मान हे

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Answered by rdsrahul15

1

Answer:

_12×(_3)+[20÷(_4)_(_24)÷8]_[16÷(_2]=(_28÷7)x

x=39

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