Question

यदि 22 gm.benjinv( C6 H6) 122 gm कार्बन टेट्राक्लोराइड ghuli हो तो बेंजीन एवं कार्बन टेट्राक्लोराइड के द्रव्यमान प्रतिशत की गणना कीजिए​

Answer 1

Given:

22 g of benzene is dissolved in 122 g of carbon tetrachloride

To find:

The mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4)

Solution:

The mass of Benzene (C₆H₆) = 22 g

The mass of Carbon Tetrachloride (CCl₄) = 122 g

∴ The mass of the solution of C₆H₆ & CCl₄ = 22 + 122 = 144 g

We have the formula to calculate the mass percentage as follows:

$\bigstar\boxed{\bold{Mass\% = \frac{Mass \:of\:solute}{Mass\:of\:solution}\times 100 }} \bigstar$

Now, using the above formula we will calculate the mass percentage of C₆H₆ & CCl₄ which is as follows:

Mass percentage of C₆H₆ is,

= $\frac{[Mass\:of\:C_6H_6]}{[Mass \:ofC_6H_6 \:+\: Mass\:of\:CCl_4]}\times 100$

= $\frac{22}{144}\times 100$

= $\bold{15.27\%}$

and

Mass percentage of CCl₄ is,

= $\frac{[Mass\:of\:CCl_4]}{[Mass \:ofC_6H_6 \:+\: Mass\:of\:CCl_4]}\times 100$

= $\frac{122}{144}\times 100$

= $\bold{84.72\%}$

Thus,

The mass % of C₆H₆ is → 15.27%.

The mass % of CCl₄ is → 84.72%.

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