Question

यदि 25 cm फोकस-दूरी के अवतल दर्पण की सहायता से सीधा (erect) प्रतिबिंब बनाना हो, तो दर्पण से वस्तु की दूरी का परास (range) क्या होना चाहिए? प्रतिबिंब की प्रकृति क्या होगी? प्रतिबिंब वस्तु से बड़ा होगा कि छोटा, इस परिस्थिति में प्रतिबिंब के बनने की क्रिया को दर्शाने के लिए एक किरण आरेख खींचें।​

Answer 1

Between pole and focus, since an erect image is only formed when the object is kept too close to the concave mirror (between focus and pole)

therefore ans for first part would be less than 25cm.

The nature of the image would be virtual since the image formed is erect.

The image formed will be bigger than the object.

 

The diagram will look something like this.

note: the name of the image is AB and object is also AB, this shows that the object is erect. If the image would have been BA, then it would be inverted. Also 2F = C, means the distance between P and F should be equal to F and C

I hope this help. PLS MARK AS BRAINLIEST