Question

यदि 29,32, 48,50 ,x,x+2, 72,78, 84,95 का माध्यम 63 है तो xका मान ज्ञात कीजिए​

Answer 1

$Given \: 29,32, 48,50 ,x,x+2, 72,78, 84,95\: का\\ माध्यम \:63$

$Number \:of \: terms \:in \:the \:data (n) \\= 10\:(even )$

$Median = Average \: of \: \frac{n}{2} \: and \\ \Big(\frac{n}{2}+1\Big)^{th} \:terms \\= Average \: of \: \frac{10}{2} \: and \\ \Big(\frac{10}{2}+1\Big)^{th} \:terms \\= Average \:of \: 5^{th} \:and \:6^{th} \:terms \\= \frac{x + x + 2 }{2} \\= \frac{2x+2}{2} \\= \frac{2(x+1)}{2} \\= x + 1 \:---(1)$

$Median = 63 \: --(2) \: ( given )$

/* From (1) and (2), we get */

$x + 1 = 63$

$\implies x = 63 - 1$

$\implies x = 62$

Therefore.,

$\red{ Value \: of \: x }\green { = 62 }$

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