यदि √3-1 और √3+1, द्विघातीय बहुपद के शून्यक हों तो बहुपद होगा: * 1 point
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Answer:
x^2-(√3-1+√3+1)x+[(√3-1)(√3+1)]
=x^2-2√3x+(3-1)
=x^2-2√3x+2.
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