यदि 3 cotA=4 जांच कीजिए कि 1 - tanA /1+tanA= cosA-cosA
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Given 3 cotA = 4.
cotA = 4/3.-------(1).
We know that tan theta = 1/cot theta
tan A = 1/cotA
= 1/4/3
= 3/4.------(2)
We know that cosec^2 theta = 1+ cot^2 = theta
= 1 + (4/3)^2
= 1 + 16/9
= 25/9.
cosec theta = 5/3.--------(3)
We know that cosec theta = 1/sin theta =
(5/3) = 1/sin theta
5sin theta = 3 =
sin theta = 3/5---------(4)
We know that cos^2 theta = 1- sin^2 theta =
= 1 - (3/5)^2
= 1 - 9/25
= 25 - 9/25
= 16/25
cos A = 4/5.-----------(5)
Now, LHS:
1-tan A
1+tanA
1-()? 1+)2
1 1+ 9 16 16
16-9 16+9
7 25
Now, RHS: (4)&(5)
cos? A - sinA
() -
16 25 9 25
16-9 25
LHS = RHS
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