Math, asked by rahulyadav2095, 4 months ago

यदि 40x² = 734² - 234² है, तो x का
मान ज्ञात कीजिए।​

Answers

Answered by shivaniguptadas
2

40x^2= 734^2 - 234^2

40x^2= (734-234) (734+234)                        [as x^2-y^2= (x-y) (x+y)

40x^2= 500*968

x^2= 500*968/40

x^2= 25*484

x^2= 12100

x= root 12100

x= 110

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