Question

यदि (54ए 81) का HCF 27 हो ता इनका
Q.22. Prow that the lengths of the tangents drawn from the external point to a circle are equal​

Answer 1

Answer:

It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact. Therefore triangle OPA is congruent to triangle OPB by RHS criterion. Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal.

Given: A circle with centre O; PA and PB are two tangents to the circle drawn from an external point P.

To prove: PA = PB

Construction: Join OA, OB, and OP.

It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.

Answer 2

Answer:

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