यदि a+1,3a,4a+2 समांतर श्रेणी में है तो a का मान ज्ञात करो और 5 पदों तक लिखो
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Answered by
1
Step-by-step explanation:
(a+1),3a,(4a+2) are in arithmetic progression.
Thus, 3a−(a+1)=(4a+2−3a)
⇒3a−a−1=a+2
⇒2a−1=a+2
⇒a=3
Answered by
1
3a-a-1=4a+2-3a
2a-1=a+2
a=3
4,9,14,19,24
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