Math, asked by shreyaSingh2022, 5 hours ago

यदि (a + b) ≠ 0 तो सिद्ध करें कि समीकरण a(x-a) = 2ab -b(x-b) का एक मूल x=a+b है।​

Answers

Answered by bambamnonaity321
0

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Answered by Salmonpanna2022
3

Step-by-step explanation:

दिया गया समीकरण है-

a(x - a) = 2ab - b(x - b)

→ ax - a^2 = 2ab - bx + b^2

→ ax + bx = a^2 + 2ab + b^2

→ (a + b)x = (a + b)^2

→ x = (a + b)^2 /a + b

[ a + b 0]

→ x = (a + b)(a + b) / (a + b)

→ x = a + b

अतः, (a + b) दिए गये समीकरण का मूहै

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