यदि ( a – b ) = 4 , तथा ab = 2 तो, ( a3 – b3) = ?
Answers
Answered by
2
Answer:
Hence, the value of a³-b³=88.
Step-by-step explanation:
∵a³-b³= (a-b)(a²+ab+ b²) ...(i)
here given, (a-b)=4 and ab =2
(a-b)²=4²
a²-2ab+b²=16
⇒a²+b²-2×2=16
⇒a²+b²=20
Now, substituting the above values in (i)
a³-b³=4×(20+2)=4×22=88
Similar questions
Chemistry,
28 days ago
Hindi,
28 days ago
Hindi,
1 month ago
CBSE BOARD XII,
9 months ago
Chemistry,
9 months ago