यदि a-b = 4 तथा ab = 21 तो a3-b3 का मान बताओ
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• (a - b) = 4
• Cubing both sides -
=> (a - b)³ = (4)³
• Using identity : (x - y)³ = x³ - y³ - 3xy(x - y),
=> a³ - b³ - 3ab(a - b) = 64
=> a³ - b³ - (3 × 21)(4) = 64
=> a³ - b³ - (3 × 21 × 4) = 64
=> a³ - b³ - 252 = 64
=> a³ - b³ = 64 + 252
=> a³ - b³ = 316
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Thank you.. ;-)
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