Question

यदि बहुपद -2x2 + kx + 2 का एक शून्यक 1 है, तो k का मान है?
If the polynomial -2x2 + kx +/2has a root 1, then what is the value of k?
2+
MI​

Answer 1

Polynomial p(X) = -2x2+kx+2

One of root is 1 therefore , -2(1)^2+ k(1) +2 =0

= -2 + k +2 = 0

= 4+k = o

K = -4

Answer 2

Answer:

Put root 1

-2(1)²+k(1)+2 = 0

-2+k+2 = 0

k = 0