यदि बहुपद p(x) =x²-23x+5 के शुन्यक a,b हो,तो ab का मान क्या होगा?
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Given : Polynomial P(x) = x² - 23x + 5
a and b are zeroes of the polynomial
To Find : Value of ab
Solution:
px² + qx + r is a polynomial
Then product of zeroes = r/p
Here x² - 23x + 5
Hence Product of zeroes = ab = 5/1 = 5
ab = 5
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