Question

यदि बहुपद x2 - kx + 8 के शून्यकों का योग 6 है, तो k का मान होगा

​

Answer 1

Answer:

6

Step-by-step explanation:

${x}^{2} - kx + 8$

Let x1 and x2 are the roots of the given equation,

then x1 + x2 = -b/a

or, 6 = k/1

or, k = 6.

HOPE IT HELPS ✌️

PLEASE MARK THE ANSWER AS BRAINLIEST. ✍️