यदि C = 3, BASK = 33, तो POSTMAN = ? (1) 98 (2) 89 (3) 110 (4) 78
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BASK =33
B+A+S+K =33.
2+1+19+11 =33 USING THE POSITION OF ALPHABETS (A IS THE FIRST ALPHABET)
( And so on )
Therefore
POSTMAN = P+O+S+T+M+A+N =16+15+19+20+13+1+14=98
Thank-you
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