Question

यदि एक समद्विबाहु त्रिभुज ABC की माध्यिका AD हो तथा A-120° एवं AB-AC हो, तो
ADB का मान ज्ञात कीजिए।
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Answer 1

In triangle ABC:

D is perpendicular to BC

therefore angle ADB=angle ADC=90°

AB=AC

angle B=angle C ( opposite angles of equal sides are also equal)

In triangle ABD:

x+60°+90°=180°

x=180°-150°=30°

angle ABD= angle ACD=30°