Question

यदि कोई वस्तु 5 cm वक्रता की त्रिज्या वाले
उत्तल दर्पण से 10 cm दूर रखी गई है, तो इसका आवर्धन कितना होगा?​

Answer 1

Answer: m= 1/5

Explanation: f=5/2 cm.

u =-10 cm

so, v = 2 cm .mirror formula se

Now , m = -v/u

m = -2/-10

m = 1/5

HENCE, Mirror ka aavardhan 1/5 hair.

Answer 2

The magnification of the convex mirror is 0.2.

Explanation:

If an object with radius of curvature of 5 cm

If the convex is placed 10 cm away from the mirror, what will be its magnification?

It is given that,

Radius of curvature of the convex mirror, R = 5 cm

Focal length of the convex mirror, f = +2.5 cm (Since, R = 2f)

Object distance from the mirror, u = -10 cm

If v is the image distance from the mirror. It can be calculated using mirror's formula such that,

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{(2.5)}-\dfrac{1}{(-10)}$

v = 2 cm

The image distance from the mirror is 2 cm. Let m is the magnification of the mirror. It is given by :

$m=\dfrac{-v}{u}$

$m=\dfrac{-2}{-10}$

m = 0.2

So, the magnification of the convex mirror is 0.2. Hence, this is the required solution.

Learn more,

Mirror's formula

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