Question

यदि किसी मंदिर की घंटी से ग्पन्न ध्वनि की आवृत्ति 400 कम्पन/सेकण्ड है, तो इसका आवर्तकाल ज्ञात कीजिए।

Answer 1

Answer:

आवर्तकाल =0.0025 sec

Explanation:

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Answer 2

The time period of the sound wave is 2.5 ms.

Explanation:

It is given that,

The frequency of the sound made by the bell of a temple is 400 vibrations / second.

To find,

Time period.

Solution,

The frequency of a sound wave is defined as the total number of vibrations per second. Mathematically, it is given by :

$T=\dfrac{1}{f}$

Here, f = 400 vibrations per seconds

$T=\dfrac{1}{400}\\\\T=2.5\times 10^{-3}\ s\\\\T=2.5\ ms$

So, the time period of the sound wave is 2.5 ms. Hence, this is the required solution.

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Time period

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