यदि किसी परमाणु में इलेक्ट्रॉनों की संख्या 9 प्रोटोन की संख्या 9 और न्यूट्रॉन की संख्या 10 है तो
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Solution :
(i) The atomic no of element = No of protons =9
(ii) The mass no of element = No of protons + No of neutrons=9+10=19
(iii) The element with Z=9 is fluorine
(f)Its electonic configuration =2,7
(iv) The valency of fluorine is 1 and is calculated as 8-7=1
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