Question

यदि log:4+ logx16 - log.64 = 12. तो x का मान ज्ञात करें।​

Answer 1

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$\large\mathcal\red{solution}$

hey there is a mistake in ur question that should be( + )in place of (- ) otherwise it will be vanished ....so...it needs to be changed.....

logx4+logx16+logx64=12

logx2²+logx2⁴+logx2^6=12

2logx2+4logx2+6logx2=12

12logx2=12

logx2=1

X¹=2

$\underline{\large\mathcal\red{hope\: this \: helps \:you......}}$