Question

यदि log a = 2 log 2 + log 3 -- log 16 है, तो 'a' का मान कितना होगा ?​

Answer 1

Answer:

$log(a) = 2log(2 ) + log(3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - log(16) \\ log(a) = log( {2}^{2} ) + log(3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - log(16 ) \\ using \: identities \\ i. \: log(m \times n) = log(m) + log(n) \\ ii. \: log \frac{m}{n} = log(m) - log(n) \\ we \: get \: \\ log(a) = log(4 \times 3) - log(16)$

$log(a) = log(12) - log(16) \\ log(a) = log \frac{12}{16} \\ log(a )= log( \frac{3}{4} ) \\ compare \: both \: the \: side \: we \: get \\ a = \frac{3}{4}$

hope this will help u........