Question

यदि NaOH की 4 ग्राम मात्रा 500 मिली विलयन में उपस्थित है, तो विलयन की
नार्मलता ज्ञात कीजिए।
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Answer 1

Given :

• Weight of NaOH = 4g
• Volume of solution = 500ml

To find :

• Normality of solution

Formula used :

• Molarity = Number of mole ÷ Volume of solution (in L)
• Normality = n factor × Molarity

Important point :

• Molar mass of NaOH = 40g/mol
• n factor for NaOH = 1

Solution :

Number of mole of NaOH = weight of NaOH ÷ Molar mass of NaOH

Number of mole of NaOH = 4 ÷ 40

Number of mole of NaOH = 0.1 mole

Molarity = Number of mole of NaOH ÷ Volume of solution (in L)

Molarity = 0.1 ÷ (500/1000)

Molarity = 0.2 M

For NaOH

Normality = nfactor× Molarity

Normality = 1 × (0.2)

Normality = 0.2N

ANSWER :

• Normality = 0.2N